CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    In the circuit shown, the currents \[{{i}_{1}}\] and \[{{i}_{2}}\]are

    A)  \[{{i}_{1}}=1.5A,{{i}_{2}}=0.5A\]

    B)  \[{{i}_{1}}=0.5A,{{i}_{2}}=1.5A\]

    C)  \[{{i}_{1}}=1A,{{i}_{2}}=3A\]

    D)  \[{{i}_{1}}=3A,{{i}_{2}}=1A\]

    Correct Answer: B

    Solution :

    Resistance \[R=\frac{12\times 4}{12+4}+2=\frac{48}{16}+2=5\,\,\Omega \] Electric current \[I=\frac{E}{R+r}=\frac{12}{6}=2\,A\]                                 \[{{I}_{1}}+{{I}_{2}}=2\,A\]                                 \[I\propto \frac{1}{R}\] \[\therefore \]  \[{{I}_{2}}=1.5\,A,\,{{I}_{1}}=0.5\,A\]    


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