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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    When an electron jumps from the orbit \[n=2\]to \[n=4\], then wavelength of the radiations absorbed will be (R is Rydberg's constant)

    A)  \[\frac{16}{3R}\]                                             

    B)  \[\frac{16}{5R}\]

    C)  \[\frac{5R}{16}\]                                             

    D)  \[\frac{3R}{16}\]

    Correct Answer: A

    Solution :

    Wavelength,      \[\frac{1}{\lambda }=R\left[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} \right]\]                                 \[\frac{1}{\lambda }=R\left[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(4)}^{2}}} \right]\]                                 \[\frac{1}{\lambda }=R\left[ \frac{1}{4}-\frac{1}{16} \right]\]                                 \[\frac{1}{\lambda }=R\left[ \frac{4-1}{16} \right]\]                                 \[\frac{1}{\lambda }=\frac{3R}{16}\]                                 \[\lambda =\frac{16}{3R}\]


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