A) \[\frac{1}{4}\]
B) \[\frac{1}{2\sqrt{2}}\]
C) \[\frac{1}{2}\]
D) \[\frac{1}{\sqrt{2}}\]
Correct Answer: D
Solution :
\[{{N}_{0}}={{2}^{n}}N\] \[N=\frac{{{N}_{0}}}{{{2}^{n}}}=\frac{{{N}_{0}}}{{{2}^{4/2}}}=\frac{{{N}_{0}}}{\sqrt{2}}\]
You need to login to perform this action.
You will be redirected in
3 sec
