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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2011

  • question_answer
    The amount of heat evolved when \[500\text{ }c{{m}^{3}}\] of \[M\text{ }HCl\] is mixed with \[200\text{ }c{{m}^{3}}\] of \[0.2\text{ }M\text{ }NaOH\] is

    A)  2.292kJ                               

    B)  1.292 kJ

    C)  22.9 kJ                                 

    D)  0.292 kJ

    Correct Answer: A

    Solution :

    No. of equivalents of \[NaOH\] reacting \[=\frac{40}{1000}\]                 \[1\,\,eq=57.3\]                 \[\frac{40}{1000}eq=\frac{57.3\times 40}{1000}=2.292\,kJ\]


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