question_answer

The resultant of two forces acting at an angle of \[{{120}^{o}}\] is 10 kg-wt and is perpendicular to one of the forces. That force is

A)  \[10\sqrt{3}\,kg-wt\]                   

B)  \[20\sqrt{3}\,kg-wt\]

C)  10 kg-wt             

D)   \[\frac{10}{\sqrt{3}}\,kg-wt\]

Correct Answer: D

Solution :

Here,     \[\tan \,{{30}^{o}}=\frac{1}{\sqrt{3}}\]                 \[\frac{1}{\sqrt{3}}=\frac{x}{10}\]                 \[x=\frac{10}{\sqrt{3}}kg-wt\]