A) 2
B) 5
C) 3
D) 1
Correct Answer: C
Solution :
Partition coefficient \[=\frac{Conc.\text{ }of\text{ }Agin\text{ }molten\text{ }Zn}{Cone.\text{ }of\text{ }Agin\text{ }molten\text{ }Pb}\] Mass of Ag in lead at equilibrium \[=1-x\] Mass of Ag in Zn at equilibrium \[=x\] \[300=\frac{x/10}{1-x/100}=\frac{10x}{1-x}\] \[10x=300\,\,(1-x)\] \[10x=300-300x\] \[x=\frac{300}{310}\] \[x=\frac{30}{31}\] Amount of silver in molten lead \[=1-x=1-\frac{30}{31}=\frac{31-30}{31}=\frac{1}{31}\] \[\therefore \] % of silver \[=\frac{1}{31}\times 100\simeq 3%\]You need to login to perform this action.
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