A) \[p{{K}_{a}}\]
B) \[p{{K}_{a}}+2\]
C) \[p{{K}_{a}}-\log \,2\]
D) \[p{{K}_{a}}+\log \,2\]
Correct Answer: D
Solution :
\[pH=p{{K}_{a}}=\frac{[salt]}{[acid]}\] When extra 0.1 mole sodium acetate is added \[\left[ salt \right]=0.2\text{ }mol\text{ }d{{m}^{-3}}\] \[\left[ acid \right]=0.1\text{ }mol\text{ }d{{m}^{-3}}\] \[\therefore \] \[pH=p{{K}_{a}}+\log \,\frac{[0.2]}{[0.1]}\] \[pH=p{{K}_{a}}+\log \,\,2\]
You need to login to perform this action.
You will be redirected in
3 sec
