A) \[Hg{{I}^{2-}}\]
B) \[HgI_{4}^{2-}\]
C) \[H{{g}^{+}}\]
D) \[H{{g}^{++}}\]
Correct Answer: B
Solution :
Nesslers reagent is \[{{K}_{2}}Hg{{I}_{4}}\]. The ion present is \[HgI_{4}^{2-}\].
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