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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2000

  • question_answer
    \[v1\] and \[v2\] are the velocities of sound at the same temperature in two monoatomic gases of densities \[\rho 1\] and \[\rho 2\] respectively. If \[\rho 1/\rho 2=\frac{1}{4},\] then the ratio of velocities v1 and v2 will be:

    A)  1 : 2

    B)  4 : 1

    C)   2 : 1

    D)  1 : 4

    Correct Answer: C

    Solution :

     Relation for the velocity of sound is \[\upsilon =\sqrt{\gamma \frac{p}{\rho }}\] hence\[\frac{{{\upsilon }_{1}}}{{{\upsilon }_{2}}}=\sqrt{\frac{{{P}_{1}}}{{{\rho }_{1}}}\times \frac{{{\rho }_{2}}}{{{P}_{2}}}}=\sqrt{\frac{4}{1}}=2:1\]


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