CET Karnataka Medical CET - Karnataka Medical Solved Paper-2000

  • question_answer
    A man suffering from short sight is unable to see objects distinctly at a distance more than 2m. The power of lens required to correct this defect of the eye should be:

    A)  + 2 D

    B)  + 0.50 D

    C)   - 2 D

    D)  - 0.5D

    Correct Answer: D

    Solution :

     Distance of vision n = 2 m                    As the man is unable to see distinctly beyond 2 m. Hence, all the objects placed beyond 2 m (i.e., \[u=\infty \]) must form an image at a distance less or equal to 2 m. The relation for focal length of a lens is                                             \[\frac{1}{f}=\frac{1}{\upsilon }-\frac{1}{u}=\frac{1}{\infty }-\frac{1}{2}=-\frac{1}{2}.\]or\[f=-2m\] Hence, the required power of a lens. \[P=\frac{1}{f}=-\frac{1}{2}=-0.5D\]


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