A) 436 to 586
B) 426 to 574
C) 436 to 574
D) 436 to 574
Correct Answer: A
Solution :
Velocity of the source is given by \[{{\upsilon }_{s}}=r\omega =r.2\pi f\] \[(f=400rev/min=\frac{400}{60}rev/sec)\]given \[=1.2\times 2\times 3.14\times \left( \frac{400}{60} \right)=50m/s\] Minimum frequency of whistle listen by man is given by \[{{n}_{\min }}=\frac{\upsilon }{\upsilon +{{\upsilon }_{s}}}=\frac{340}{340+50}\times 500=435.89Hz\] \[\approx 436Hz\] Maximum frequency of whistle listen by man is given by \[n\max =\frac{\upsilon }{\upsilon -{{\upsilon }_{s}}}=\frac{340}{340-50}\times 500=586.20\] \[\approx 586Hz\]
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