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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2000

  • question_answer
    The force required to separate two glass plates of area \[{{10}^{-2}}{{m}^{2}}\]with a film of water 0.05 mm thick between them, is (Surface tension of water is\[70~\times {{10}^{-3}}N/m\])

    A)  28 N

    B)  14 N

    C)   50 N

    D)  38 N

    Correct Answer: A

    Solution :

     Force required to separate the plates \[F=\frac{2TA}{a}\] Given : area, \[A={{10}^{-2}}{{m}^{2}}\]thickness \[d=0.05mm=0.05\times {{10}^{-3}}m\] So, \[F=\frac{2\times 10\times {{10}^{-3}}\times {{10}^{-2}}}{0.05\times {{10}^{-3}}}\]\[=28N\]


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