A) \[300ml\]. \[{{H}_{2}}\] and\[200ml\]. \[N{{H}_{3}}\]
B) \[300ml.\]\[{{H}_{2}}\] and \[300ml.\]. \[N{{H}_{3}}\]
C) \[100ml.\]. \[{{H}_{2}}\] and \[100ml.\]. \[N{{H}_{3}}\]
D) \[100ml.\]\[{{H}_{2}}\] and \[200ml.\]. \[N{{H}_{3}}\]
Correct Answer: A
Solution :
\[{{N}_{2}}(g)+3{{H}_{2}}(g)\rightleftharpoons 2N{{H}_{3}}(g)\] The quantity of \[{{N}_{2}}(g)\] reacted\[=100\text{ }ml\] \[\therefore \] The quantity of \[{{H}_{2}}(g)\]is three times \[=300\text{ }ml\] and \[N{{H}_{3}}\] produced \[=200ml\]
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