A) \[10:1\]
B) \[1:10\]
C) \[4:5\]
D) \[5:4\]
Correct Answer: D
Solution :
\[_{p}Ka\] of weak acid \[=4.0\] We know that \[pH{{=}_{p}}Ka+\log \frac{salt}{acid}\] Here, \[pH=5,{{\,}_{p}}{{K}_{a}}=4\] \[5=4+1,\log \frac{salt}{acid}=1,\] \[\therefore \] \[\frac{salt}{acid}=\frac{10}{1}\]
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