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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    5 moles of \[S{{O}_{2}}\] and 5 moles of \[{{O}_{2}}\] are allowed to react to form \[S{{O}_{3}}\] in a closed vessel. At the equilibrium stage 60% of \[S{{O}_{2}}\] is used up. The total number of moles of \[S{{O}_{2}},{{O}_{2}}\] and \[S{{O}_{3}}\] in the vessel now is:

    A)  \[10.0\]           

    B)  \[8.5\]

    C)  \[10.5\]       

    D)  \[3.9\]

    Correct Answer: B

    Solution :

    \[2S{{O}_{2}}+{{O}_{2}}\rightleftharpoons 2S{{O}_{3}}\] At equilibrium 60% of \[S{{O}_{2}}\] is used up 5 moles of \[S{{O}_{2}}\] and 5 moles of \[{{O}_{2}}\] react to form \[S{{O}_{3}}\] Hence, \[\underset{5}{\mathop{2S{{O}_{2}}}}\,+\underset{5}{\mathop{{{O}_{2}}}}\,\rightleftharpoons \underset{-}{\mathop{2S{{O}_{3}}}}\,\] 60% of 5 moles =5 moles
    initial  \[2x\] \[x\] \[2x\]
    used up concentration \[3\] \[1.5\] \[2\times 1.5\]
    at equilibrium \[2\] \[3.5\] \[3\]
    \[\therefore \] Total number of molecules \[=2+3.5+3=8.5\]


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