A) \[16.25J\]
B) \[16.25kJ\]
C) \[32.5J\]
D) \[32.5kJ\]
Correct Answer: B
Solution :
The enthalpy of combustion of \[{{C}_{6}}{{H}_{6}}(l)=3250kJ\] By burning 78 gm. of \[{{C}_{6}}{{H}_{6}}\] liberated heat =3250 kJ [Mol. wt. of benzene \[=12\times 6+1\times 6=78\]] On buring 0-39 gm. of \[{{C}_{6}}{{H}_{6}}\] liberated heat \[=\frac{0.39}{78}\] \[=3250\] \[=16.25kJ\]
You need to login to perform this action.
You will be redirected in
3 sec
