A) ethene
B) ethoxy ethane
C) ethyne
D) ethane
Correct Answer: A
Solution :
\[\underset{Ethanol}{\mathop{C{{H}_{3}}C{{H}_{2}}OH}}\,\xrightarrow[{{170}^{o}}C]{Con.\,{{H}_{2}}S{{O}_{4}}}\underset{\begin{smallmatrix} Ethylene \\ (Ethene) \end{smallmatrix}}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]You need to login to perform this action.
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