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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    In an experiment with Kunds tube, the distance between consecutive nodes is 5 cm, when air is inside and it is 13.4 cm, when hydrogen is inside then the velocity of sound in hydrogen will be   (velocity  of  sound  in  air = 330 m/s):

    A)  884.4 m/s

    B)  984.4 m/s

    C)  1084.4 m/s

    D)  none of these

    Correct Answer: A

    Solution :

     Distance between two consecutive nodes with air \[{{l}_{A}}=5cm.\] Distance between two consecutive nodes with hydrogen \[{{l}_{A}}=13.4cm.\] Velocity of sound in air = 330 m/s The velocity of sound is given by \[\upsilon H={{\upsilon }_{A}}\frac{{{l}_{H}}}{{{l}_{A}}}=330\times \frac{13.4}{5}\] \[=884.5m/s\]


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