CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    The resistors of resistances 2\[\Omega \], 4\[\Omega \] and 8\[\Omega \] are connected in parallel, then the equivalent    resistance of the combination will be:

    A)  \[\frac{8}{7}\Omega \]

    B)  \[\frac{7}{8}\Omega \]

    C)   \[\frac{7}{4}\Omega \]

    D)  \[\frac{4}{9}\Omega \]

    Correct Answer: A

    Solution :

     First resistance \[{{R}_{1}}=2\Omega \] Second resistance \[{{R}_{2}}=4\Omega \] Third resistance \[{{R}_{3}}=8\Omega \] (given) These three resistances are connected in parallel. As the relation for the equivalent resistance of parallel combination is given by \[\frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}+\frac{1}{{{R}_{3}}}=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}\] \[=\frac{7}{8}\] Thus \[R=\frac{8}{7}\Omega \]


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