A) 5 : 4
B) 4 : 3
C) 3 : 2
D) 2 : 3
Correct Answer: C
Solution :
Given : Power of first bulb \[{{P}_{1}}=40\]watt Power of second bulb \[{{P}_{2}}=40\] watt As the power of the bulb is given by \[P=\frac{V}{R}\propto \frac{1}{R}\] Hence \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{R}_{2}}}{{{R}_{1}}}.\]or\[\frac{40}{60}=\frac{{{R}_{2}}}{{{R}_{1}}}\]or\[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{60}{40}=\frac{3}{2}\]or\[{{R}_{1}}:{{R}_{2}}=3:2\]
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