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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    A train is moving towards north with a speed of 180 km/hr. If the vertical component of the earths magnetic field is \[0.2\times {{10}^{-4}}\] the e. m. f. induced, in the axle 1-5 m long, is:

    A)  1.5 mV

    B)  15 mV

    C)  5.4 mV

    D)  54 mV

    Correct Answer: A

    Solution :

     Given : Length of the axle \[l=1.5m\] The magnetic field \[B=0.2\times {{10}^{-4}}\] tesla The speed of the train = 180 km/hour \[=180\times \frac{5}{18}=50m/s\] From the formula e.m.f. is given by \[E=B\upsilon l\] \[=0.2\times {{10}^{-4}}\times 50\times 1.5\] \[=1.5\times {{10}^{-3}}=1.5mV\]


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