A) \[{{I}_{E}}=9mA,\,{{I}_{B}}=-1mA\]
B) \[{{I}_{E}}=-1mA,\text{ }{{I}_{B}}=9mA\]
C) \[{{I}_{E}}=1\text{ }mA,\text{ }{{I}_{B}}=11mA\]
D) \[{{I}_{E}}=11mA,\text{ }{{I}_{B}}=1mA\]
Correct Answer: D
Solution :
Collector current\[{{I}_{C}}=10mA=0.9{{I}_{E}}\](where \[{{I}_{E}}\] the emitter current) Thus \[{{I}_{E}}=\frac{10}{0.9}=11mA\] For an-p-n transistor base current is given by \[{{I}_{B}}={{I}_{E}}-{{I}_{C}}=11-10=1mA\]
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