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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    The frequency of a tuning fork is 384 per second and velocity of sound in air is 352 m/s. How far the sound has traversed while fork completes 36 vibration?

    A)  3 m

    B)  13 m

    C)  23 m

    D)  33 m

    Correct Answer: D

    Solution :

     Distance traversed in one vibration is \[\lambda =\frac{\upsilon }{n}=\frac{352}{384}\] Distance traversed in 36 vibration \[s=36\lambda =36\times \frac{352}{384}=33m\]


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