CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    \[_{p}{{K}_{a}}\] values of two acids A and B are 4 and 5. The strengths of these two acids are related as:

    A)  acid A is 10 times stronger than acid B

    B)  strength of acid A : strengths of acid \[B=4:5\]

    C)  the strengths of the two acids can not be compared

    D)  acid B is 10 times stronger than acid A

    Correct Answer: A

    Solution :

    \[_{p}{{K}_{a}}\] of acid \[A=4\] \[_{p}{{K}_{a}}\] of acid \[B=5\] We know that \[_{p}{{K}_{a}}=-\log {{K}_{a}}\] or   \[{{K}_{a}}={{10}^{{{-}_{p}}{{K}_{a}}}}\]       \[\therefore \] acid A,  \[{{K}_{a}}={{10}^{-4}}\] acid B,  \[{{K}_{a}}={{10}^{-5}}\] Hence A, is ten times stronger than B


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