A) \[3.3\]
B) \[4.3\]
C) \[4.0\]
D) \[4.5\]
Correct Answer: A
Solution :
Aqueous solution of pH 6 means, \[[{{H}^{+}}]={{10}^{-6}}\]: Aq. solution of pH 3 means, \[[{{H}^{+}}]={{10}^{-3}}\] Aq. solutions of both pH are mixed in equal volume, hence \[[{{H}^{+}}]=\frac{{{10}^{-6}}+{{10}^{-3}}}{2}\] \[={{10}^{-6}}\left( \frac{1+{{10}^{3}}}{2} \right)\] or \[={{10}^{-6}}\times \frac{1001}{2}={{10}^{-6}}\times 550\] \[pH=-\log [{{H}^{+}}]\] \[=6-\log 550\] \[=6-2.7404\] \[=3.2596\] \[=3.3\]
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