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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2001

  • question_answer
    In order to decompose 9g water \[142.5\text{ }kJ\]heat is required. Hence the enthalpy of formation of water is:

    A)  \[-142.5\text{ }kJ\]

    B)  \[+142.5\text{ }kJ\]

    C)  \[-285kJ\]      

    D)  \[+285kJ\]

    Correct Answer: C

    Solution :

    For the decomposition of 9 gm of water heat required \[=142.5kJ\] We know that the molecular weight of \[{{H}_{2}}O=2+16=18\] Therefore,    heat    required  for decomposition of 18 gm of water \[=\frac{18}{9}\times 142.5=285kJ\] Therefore, enthalpy of formation of water \[=-285kJ\]


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