A) \[45g\]of \[MgO\]and \[15g\]of \[{{O}_{2}}\]
B) \[50g\]of \[MgO\] and \[10g\]of \[{{O}_{2}}\]
C) \[60g\] of \[MgO\] only
D) \[40g\] of \[MgO\] and \[20g\] of \[{{O}_{2}}\].
Correct Answer: B
Solution :
\[Mg\] and oxygen reacts as \[\underset{(48)}{\mathop{\underset{2\times 24}{\mathop{2Mg}}\,}}\,+\underset{(32)}{\mathop{\underset{32}{\mathop{{{O}_{2}}}}\,}}\,\xrightarrow{{}}\underset{(80)}{\mathop{\underset{2\times 40}{\mathop{2MgO}}\,}}\,\] \[48gm\]of \[Mg\] produce \[80gm\]of \[MgO\] \[32gm\]\[\therefore \]\[30gm\] of \[Mg\] produce \[\frac{80\times 30}{48}=50gm.\] \[\because \] \[48gm\]of \[Mg\]reacts with \[32gm\]of oxygen \[\therefore \] \[30gm\]of \[Mg\] reacts with \[\frac{32\times 30}{48}=10gm\]
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