A) \[Z=12,\text{ }M=27\]
B) \[Z=13,\text{ }M=27\]
C) \[Z=12,M=17\]
D) \[Z=13,M=28\]
Correct Answer: B
Solution :
\[_{Z}{{X}^{M}}{{+}_{2}}H{{e}^{4}}{{\xrightarrow{{}}}_{15}}{{P}^{30}}{{+}_{0}}{{n}^{1}}\] Here \[Z=13\] and \[M=17\] Hence \[_{13}{{X}^{17}}{{+}_{2}}H{{e}^{4}}{{\xrightarrow{{}}}_{15}}{{P}^{30}}{{+}_{0}}{{n}^{1}}\]
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