A) \[{{v}_{O}}=4\upsilon H\]
B) \[{{\upsilon }_{H}}=4{{\upsilon }_{O}}\]
C) \[{{\upsilon }_{O}}={{\upsilon }_{H}}\]
D) \[{{\upsilon }_{H}}=16{{v}_{O}}\]
Correct Answer: B
Solution :
\[{{\upsilon }_{O}}=\sqrt{\frac{3RT}{{{M}_{O}}}}{{M}_{H}}=2,{{M}_{O}}=32\] \[{{\upsilon }_{H}}=\sqrt{\frac{3RT}{{{M}_{H}}}}\] \[\frac{{{\upsilon }_{O}}}{{{\upsilon }_{H}}}=\sqrt{\frac{{{M}_{H}}}{{{M}_{O}}}}=\sqrt{\frac{2}{32}}=\frac{1}{4}\] \[{{\upsilon }_{H}}=4{{\upsilon }_{O}}\]
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