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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2002

  • question_answer
    A Carnots engine is made to work between \[200{}^\circ C\] and \[0{}^\circ C\] first and then between \[0{}^\circ C\] and \[-200{}^\circ C\]. The ratio of efficiencies of the engine in the two cases is:

    A)  1 : 173

    B)  1.73 : 1

    C)   1 : 2

    D)  1 : 1

    Correct Answer: A

    Solution :

    \[{{T}_{1}}=200+273={{473}^{o}}K\] \[{{T}_{2}}=0+273={{273}^{o}}K\] \[{{\mu }_{1}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}=42.2%\] For second \[{{T}_{1}}=0+273={{273}^{o}}K\] \[{{T}_{2}}=-200+273={{73}^{o}}K\] \[{{\mu }_{2}}=1-\frac{{{T}_{2}}}{{{T}_{1}}}\]\[=73.2%\] \[\frac{{{\mu }_{1}}}{{{\mu }_{2}}}=\frac{42.2}{73.2}=\frac{1}{1.73}\] \[{{\mu }_{1}}:{{\mu }_{2}}=1:1.73\]


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