A) \[0.02N\]acidic
B) \[0.025\]N basic
C) \[0.02\text{ }N\]basic
D) \[0.025\text{ }N\]acidic
Correct Answer: C
Solution :
\[{{V}_{1}}=20ml,{{N}_{1}}=0.25N,\,{{V}_{2}}=30ml\], \[{{N}_{2}}=0.2N\] \[\because \]\[N=\frac{{{N}_{1}}{{V}_{1}}+{{N}_{2}}{{V}_{2}}}{{{V}_{1}}+{{V}_{2}}}=\frac{20(0.25)+30(0.2)}{20+30}\] \[=\frac{5+6}{50}=\frac{11}{50}=0.2N\],basicYou need to login to perform this action.
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