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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2003

  • question_answer
    If v is the speed of sound in air then the shortest length of the closed pipe which resonates to a frequency n, is:

    A)  \[\frac{v}{2n}\]

    B)  \[\frac{v}{4n}\]

    C)  \[\frac{4n}{v}\]

    D)  \[\frac{2n}{v}\]

    Correct Answer: B

    Solution :

    In closed orgen pipe       \[n=\frac{\upsilon }{4l}\] So           \[l=\frac{\upsilon }{4n}\]


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