question_answer

In the circuit as shown in the figure, the effective capacitance between A and B is:

A)  2\[\mu \]F

B)  2\[\mu \]F

C)  8\[\mu \]F

D)  4\[\mu \]F

Correct Answer: D

Solution :

From figure, the effective capacitance of \[{{C}_{1}},{{C}_{2}}\] and  \[{{C}_{3}}\] is given by \[\frac{1}{C}=\frac{1}{4}+\frac{1}{2+2}=\frac{1}{2}\] \[\Rightarrow \] \[C=2\mu F\] Effective capacitance of \[{{C}_{4}}\] and \[{{C}_{5}}\] is \[\frac{1}{C}=\frac{1}{4}+\frac{1}{4}=\frac{1}{2}\] or         \[C=2\mu F\] Now effective capacitance between A and B \[C=C+C\] \[C=(2+2)\mu F=4\mu F\]