A) \[152\]
B) \[56\]
C) \[168\]
D) \[68\]
Correct Answer: C
Solution :
Atomic weight of element, M = equivalent weight \[\times \] valency \[=20\times 3\] \[=60\] Molecular formula of its oxide \[={{M}_{2}}{{O}_{3}}\] Hence, molecular weight of oxide \[=2\times 60+3\times 12\] \[=120+48\]You need to login to perform this action.
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