A) 3 parts of \[A{{l}_{2}}{{O}_{3}}\]and 4 parts of \[Al\].
B) 3 parts of \[F{{e}_{2}}{{O}_{3}}\]and 2 parts of \[Al\]
C) 3 parts of \[F{{e}_{2}}{{O}_{3}}\] and 1 part of \[Al\]
D) 1 part of \[F{{e}_{2}}{{O}_{3}}\] and 1 part of \[Al\]
Correct Answer: C
Solution :
Goldschmidt in 1905 discovered a method for the reduction of haematite \[(F{{e}_{2}}{{O}_{3}})\] with aluminium metal. The process is known as alumino thermic process, as in this process, large heat is produced. In this, \[F{{e}_{2}}{{O}_{3}}\] and aluminium are taken in \[3:1\]ratio and this mixture, known as thermite, is ignited to initiate the reaction, when \[F{{e}_{2}}{{O}_{3}}\] is reduced to molten Fe. \[2Al+F{{e}_{2}}{{O}_{3}}\xrightarrow{{}}A{{l}_{2}}{{O}_{3}}+\underset{molten}{\mathop{2Fe+3230kJ}}\,\]
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