A) \[{{C}_{2}}{{H}_{6}}\]
B) \[C{{H}_{4}}\]
C) \[{{C}_{2}}{{H}_{2}}\]
D) \[{{C}_{2}}{{H}_{4}}\]
Correct Answer: D
Solution :
Ethylene is formed by dehydrohalogenation of alkyi halide in presence of alcoholic \[KOH\]. Ethylene decolourise alkaline \[KMn{{O}_{4}}\] due to get oxidized by it. \[C{{H}_{3}}-C{{H}_{2}}I\xrightarrow{Alc.\,KOH}\underset{ethylene}{\mathop{C{{H}_{2}}=C{{H}_{2}}}}\,\]
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