A) 128 times
B) 100 times
C) 500 times
D) 250 times
Correct Answer: A
Solution :
Temperature coefficient \[=\frac{rate\,of\,reaction\,at\,{{35}^{o}}C}{rate\,of\,reaction\,at\,{{25}^{o}}C}=2\] Thus, increase in rate is 2 times, when temperature is increased \[{{10}^{o}}C\]. Hence, by the increase of\[{{70}^{o}}C\]\[{{70}^{o}}C(100-30={{70}^{o}}C)\], the increase in rate will be \[={{(2)}^{7}}\] (\[\because \] \[{{70}^{o}}=7\times {{10}^{o}}\]) \[=128\]times
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