A) \[450c{{m}^{3}}\]
B) \[100c{{m}^{3}}\]
C) \[45c{{m}^{3}}\]
D) \[400c{{m}^{3}}\]
Correct Answer: D
Solution :
Let, x ml of \[HCl\] are taken, then \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[\frac{1}{2}\times x=\frac{1}{10}\times 500\] \[\frac{1}{2}\times x=\frac{1}{10}\times 500\] \[x=10mL\] Hence, water needed to add \[=500-100=400mL\]
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