CET Karnataka Medical CET - Karnataka Medical Solved Paper-2003

  • question_answer
    The percentage s-character of the hybrid orbitals in methane, ethene and ethyne are respectively:

    A)  \[25,33,50\]

    B)  \[25,50,75\]

    C)  \[50,75,100\]

    D)  \[10,20,40\]

    Correct Answer: A

    Solution :

    In methane, ethene and ethyne, the hybridisations are respectively \[s{{p}^{3}},s{{p}^{2}}\] and sp. Hence % s-character will be \[s{{p}^{3}}=\frac{1}{4}\times 100=25%\] \[s{{p}^{2}}=\frac{1}{3}\times 100=33%\] \[sp=\frac{1}{2}\times 100=50%\]


You need to login to perform this action.
You will be redirected in 3 sec spinner