A) 2 : 1
B) 3 : 1
C) 1 : 3
D) 1 : 1
Correct Answer: A
Solution :
Kinetic energy of a body \[E=\frac{1}{2}m{{\upsilon }^{2}}\] \[=\frac{1}{2m}{{(m\upsilon )}^{2}}\] \[=\frac{{{p}^{2}}}{2m}\] \[(\because p=m\upsilon )\] or \[E\propto \frac{1}{m}\][ p = constant (given)] \[\therefore \] \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{{{m}_{2}}}{{{m}_{1}}}\] \[=\frac{2}{1}\]
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