A) \[{{C}^{2}}{{m}^{2}}{{N}^{2}}\]
B) \[{{C}^{2}}{{m}^{-2}}{{N}^{-1}}\]
C) \[{{C}^{2}}{{m}^{2}}{{N}^{-1}}\]
D) \[{{C}^{-1}}{{m}^{2}}{{N}^{-2}}\]
Correct Answer: B
Solution :
From Coulombs law \[F=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{{{q}_{1}}{{q}_{2}}}{{{r}^{2}}}\]or\[{{\varepsilon }_{0}}=\frac{{{q}_{1}}{{q}_{2}}}{4\pi F{{r}^{2}}}\] \[\therefore \]Units of \[{{\varepsilon }_{0}}\] (permittivity) \[=\frac{{{C}^{2}}}{N-{{m}^{2}}}={{C}^{2}}{{N}^{-1}}{{m}^{-2}}\]
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