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CET Karnataka Medical CET - Karnataka Medical Solved Paper-2004

  • question_answer
    The maximum current that can be measured by a galvanometer of resistance 40\[\Omega \], is 10 mA. It is converted into a voltmeter that can read upto 50 V. The resistance to be connected in series with the galvanometer (in ohms) is:

    A)  2010

    B)  4050

    C)  5040

    D)  4960

    Correct Answer: D

    Solution :

    To convert a galvanometer into voltmeter, the necessary value of resistance to be connected   in   series   with   the galvanometer is \[R=\frac{V}{{{I}_{g}}}-G=\frac{50}{10\times {{10}^{-3}}}-40\] \[=5000-40=4960\Omega \]


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