A) \[11.46kJ\]
B) \[57.3kJ\]
C) \[573\text{ }kJ\]
D) \[573J\]
Correct Answer: D
Solution :
The number of gram-equivalents of \[{{H}_{2}}S{{O}_{4}}=0.2\times \frac{50}{1000}=1.0\times {{10}^{-2}}\] The number of gram-equivalents of \[KOH=1\times \frac{50}{1000}\] \[=5\times {{10}^{-2}}\] We know that \[57.3kj\]heat is evolved when one gram-equivalent of strong acid (like \[{{H}_{2}}S{{O}_{4}}\]) and one gram-equivalent of strong base (like KOH) are neutralised. Here \[1.0\times {{10}^{-2}}\] gram-equivalent of \[{{H}_{2}}S{{O}_{4}}\] is neutralised by \[1.0\times {{10}^{-2}}\] gram-equivalent of \[KOH\] hence the heat evolved will be \[=57.3kj\times 1.0\times {{10}^{-2}}\] \[=57.3\times {{10}^{3}}\times {{10}^{-2}}j\] \[=57.3j\]
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