A) \[PC{{l}_{5}}\]
B) \[C{{l}_{2}}\]
C) \[SOC{{l}_{2}}\]
D) \[PC{{l}_{3}}\]
Correct Answer: B
Solution :
\[PC{{l}_{3}}.PC{{l}_{5}}\] and \[SOC{{l}_{2}}\] are used to replace -group of an alcohol or an acid by \[-Cl\]group \[R-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH+PC{{l}_{5}}\xrightarrow{{}}R-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-Cl\] \[+POC{{l}_{3}}+HCl\] \[R-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-OH+SOC{{l}_{2}}\to R-\overset{O}{\mathop{\overset{||}{\mathop{C}}\,}}\,-Cl\] \[+S{{O}_{2}}+HCl\] when acid reacts with \[C{{l}_{2}}\] in presence of red phosphorus, \[\alpha \]-chloroacid is obtained. (Hall-Vohlard Zeiinsky reaction). \[C{{H}_{3}}C{{H}_{2}}COOH+C{{l}_{2}}\xrightarrow[\Delta ]{rad\,S}\] \[\underset{\alpha -chloropropionic\,acid}{\mathop{C{{H}_{3}}\overset{Cl}{\mathop{\overset{|}{\mathop{C}}\,}}\,HCOOH+HCl}}\,\]
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