A) Fluorine
B) iodine
C) Chlorine
D) bromine
Correct Answer: B
Solution :
Nitric acid oxidise iodine into iodic acid \[(HI{{O}_{3}})\]. \[10HN{{O}_{3}}+{{I}_{2}}\xrightarrow{{}}\underset{Iodic\,acid}{\mathop{3HI{{O}_{3}}}}\,+10N{{O}_{2}}+4{{H}_{2}}O\]
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