A) \[Al\]
B) \[Fe\]
C) \[Pb\]
D) \[Mg\]
Correct Answer: C
Solution :
\[Al\], \[Fe\], \[Mg\] all reduce dilute \[HN{{O}_{3}}\] into \[N{{H}_{4}}N{{O}_{3}}\] while Pb gives \[N{{O}_{2}}\] with dilute nitric acid. \[3Pb+\underset{dilute}{\mathop{8NH{{O}_{3}}}}\,\to 3Pb{{(N{{O}_{3}})}_{2}}+2NO+4{{H}_{2}}O\]
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