A) Ethyl benzoate
B) Ethyl formate
C) Ethyl acetate
D) Methyl acetate
Correct Answer: A
Solution :
The reaction occurs as follows: \[\underset{ethyl\,benzoate}{\mathop{{{C}_{6}}{{H}_{5}}COO{{C}_{2}}{{H}_{5}}}}\,+KOH\xrightarrow{\Delta }{{C}_{6}}{{H}_{5}}COOK\] \[+{{C}_{2}}{{H}_{5}}OH\] \[{{C}_{6}}{{H}_{5}}COOK+HCl\to \underset{while\,soild}{\mathop{{{C}_{6}}{{H}_{5}}COOH+KCl}}\,\]
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