A) Colourblindness
B) O blood group
C) Albinism
D) \[R{{h}^{+}}\] blood group
Correct Answer: D
Solution :
As cell size increases, volume grows much more rapidly than does the cell surface area. For a round cells surface area increases as the square of the diameter whereas volume increases as the cube When diameter is \[=2{{\mu }^{2}}\] surface area \[={{2}^{2}}=2\times 2=4{{\mu }^{2}}\] volume \[={{2}^{3}}=2\times 2\times 2=4{{\mu }^{3}}\] surface-volume ratio \[=\frac{4}{8}=\frac{1}{2}\] when diameter is\[=4{{\mu }^{2}}\] surface area \[={{4}^{2}}=4\times 4=16{{\mu }^{2}}\] volume \[={{4}^{3}}=4\times 4\times 4=64{{\mu }^{\text{3}}}.\] surface-volume ratio \[=\frac{1}{4}\] Thus, when a cell of diameter \[2\mu \] grows to double its diameter, its surface area-volume ratio will reduce to half.
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