A) 200
B) 100
C) 10
D) 50
Correct Answer: B
Solution :
Let the resistance of voltmeter is \[G\Omega .\] \[\therefore \]Total resistance of the circuit \[R=\left( \frac{G\times 100}{G+100}+50 \right)\Omega \] Total current \[i=\frac{V}{R}\] \[=\frac{10}{\left( \frac{G\times 100}{G+100}+50 \right)}\] Voltage across \[100\,\Omega \] resistance \[=i\left( \frac{G\times 100}{G+100} \right)=\frac{10}{\left( \frac{G\times 100}{G+100}+50 \right)}\times \left( \frac{G\times 100}{G+100} \right)\] Reading of voltmeter =5 volts \[\therefore \] Voltage across \[100\Omega =5\]volts \[5=\frac{10}{\left( \frac{G\times 100}{G+100}+50 \right)}\times \left( \frac{G\times 100}{G+100} \right)\]\[\therefore \] On solving \[G=100\Omega \]
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