CET Karnataka Medical CET - Karnataka Medical Solved Paper-2005

  • question_answer
    The adjacent figure is the part of a horizontally stretched net. Section AB is stretched with a force of 10 N. The tensions in the sections BC and BF are:

    A)  10 N, 11 N

    B)  10 N, 6 N

    C)  10 N, 10 N

    D)  cant be calculated due to insufficient data

    Correct Answer: C

    Solution :

    From the figure. \[{{T}_{1}}\cos {{30}^{o}}={{T}_{2}}\cos {{30}^{o}}\] \[\therefore \] \[{{T}_{1}}={{T}_{2}}=T\](Let) Again\[{{T}_{1}}\sin {{30}^{o}}+{{T}_{2}}\sin {{30}^{o}}=10\] \[2T\sin {{30}^{o}}=10\] \[2T.\frac{1}{2}=10\Rightarrow T=10N\] \[\therefore \] Tension in section BC and BF are 10 N and ION


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